\textrm{For the block diagrm shown in the figure, the transfer function }\;\frac{Y(s)}{R(s)} is
(A) \frac{2S+3}{S+1}\;\;\;\;\;\;(B)\frac{3S+2}{S-1}\\\;\\(C)\frac{S+1}{3S+2}\;\;\;\;\;(D)\frac{3s+2}{S+1}\\\;\\Note: Answer in Commet
AJAZ UL HAQ Changed status to publish April 15, 2023
Solution of Gate EE 2023 Question paper \\\;\\Step 1 \\\;\\Draw single Flow graph \\\;\\\\\;\\Step 2 \\\;\\Transfer functions of Forward paths\\\;\\P_{1}=3\;\;\Delta_{1}\\\;\\P_{2}=\frac{2}{s}\;\;\Delta_{2}\\\;\\\textrm{Loop}, L_{1}=\frac{1}{s}\\\;\\ Using Masson’s gain formula \\\;\\\frac{Y(s)}{R(s)}=\frac{P_{1}\Delta_{1}+P_2\Delta_2}{1-L_1} = \frac{3S+2}{S - 1}
AJAZ UL HAQ Changed status to publish April 27, 2023